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To keep the product of 2 numbers same, If one is increased by 40% then by what % will the

 2^{nd} be decreased
bout the Q
or do you know how to solve it
just lik SHERON
wait let me just find out the process from book


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Let the two numbers be X and Y.
product = XY
let X is decreased by 40%
40% of X = (40/100)× X = 40X/100 = 0.4X
by reducing X by 40%, it becomes x
x = X - 0.4X = 0.6X

Let Y becomes y after increasing.
xy = XY
⇒ 0.6X × y = XY
⇒ y = XY/0.6X
⇒ y = Y/0.6 = 10Y/6 
⇒y = = 5Y/3

% increase =  \frac{ \frac{5Y}{3}  -Y}{Y} *100= \frac{ \frac{5Y-3Y}{3} }{Y} *100= \frac{2Y}{3Y} *100= \frac{100*2}{3} =66.7%
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