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A 2kg circular magnet is attached to a vertical metallic board by magnetic force F(m)=16 N as shown in the diagram below. the magnet is then the coefficent

of friction between the magnet and the board?(g=10mls2)



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The magnetic force is horizontal and is 16 N. This gives the normal reaction force on magnet exerted by the board. 

Frictional force between board and magnet = μ N = μ 16 Newtons

Weight of magnet = 2 * 10 Newtons.

They are in equilibrium and hence the magnet is stationary.
 Hence   16 μ = 20    =>  μ = 1.25        ( it is very high because of magnetic effect)

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