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You can see x/a + y/b + z/c = (b-c) + (c-a) + (a-b) = 0. You might be knowing a common algebraic property p+q+r=0 ⇔ p³+q³+r³=3pqr. From this you have (x/a)³+(y/b)³+(z/c)³=3(x/a)(y/b)(z/c). Hence, answer is 3(a-b)(b-c)(c-a)
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