Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Let s=2+3+6+11+18............tn s= 2+3+ 6 +11+18......tn-1+tn subtract the above two equations and you will notice that difference is in A.P. that is 1,3,5,7...and hence you can solve

you can subtract the above 2 equation which i have said and after that you will get Tn=1+3+5+7.......as i said earlier.so tn is n/2{2a+(n-1)d......this is the general term of the above ap.......now put the required values of a=1 and d=2 in Tn which i have written......you will get Tn as n^2-n...but still check the calculations ans now Sn is sigma Tn ans so sigma n^2 is n(n+1)(2n+1)/6 and sigma n is n(n+1)/2............but still check the calculations and on adding put n=50 and u are there....