Answers

2014-11-02T20:36:16+05:30
Critical angle is given by 
n=1/sinC
sinC= 1/n                      n=4/3
sin C= 3/4
C = sin inverse(3/4)
C= 48.5 degresss
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r u sure??
Why is there some mistake??
2014-11-02T21:39:08+05:30

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Critical angle  is possible when light rays pass from  glass into air.  Hence according to the law of refraction we have:

\mu_{glass}\ Sin\ i = \mu_{air}\ Sin\ r\\\\r= \pi /2,\mu_{air}=1\ \ ,\ i_{C}=Critical\ angle\ in\ glass.\\\\ i_{C} =Sin^{-1}\ (1/\mu_{glass})

\mu_{glass}=1.3\ to\ 1.6\ \ in\ general.\\ \\For\ \mu_{glass}=1.3,\ \ i_C=sin^{-1}(1/1.3)=50.3\deg\\\\For\ \mu_{glass}=1.6,\ \ i_C=sin^{-1}(1/1.6)=38.7\deg\\
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