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First and second ionisation energies of magnesium are 7.646 and 15.035 eV respectively. The amount of energy in kJ needed to convert all the atoms of

magnesium into Mg2+ ions present in 12 mg of magnesium vapours is:[Given : 1eV = 96.5 kJ mol-1]


The answer which I give maybe wrong as I am still a novice.
Add the electron volts and multiply it with 96.5 and keep the result aside.Then fid the no of moles by unitary method.
You will get 0.1mol.
now multiply the result with 0.1 and I got the answer as 218.87165 kJ.
Sorry if I am wrong.
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