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1) Horizontal is same for angle of projection θ and (90-θ).

2) a shell is fired at an angle 30° to the horizontal with a velocity 196 m/s. Find the total time of flight, horizontal range and maximum height attained?

we know that range=(u)square sin 2tita /g then according to question, range=(196)(196)( sin 2(30))/10 we know g=10 =38416 (root3)/2 /10 =38416(1.7320)/20 t=2u sin(tita)/g =2(196)sin(30)/10 =392(1/2) /10 h max=(u) square( sin) square (tita)/2g =(196)square (sin)square(30)/2(10) =38416(1/2)(1/2)/20

We know that range=(u)square sin 2tita /g then according to question, range=(196)(196)( sin 2(30))/10 we know g=10 =38416 (root3)/2 /10 =38416(1.7320)/20 t=2u sin(tita)/g =2(196)sin(30)/10 =392(1/2) /10 h max=(u) square( sin) square (tita)/2g =(196)square (sin)square(30)/2(10) =38416(1/2)(1/2)/20

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Angle of projection (α) = 30 velocity (u) = 196 m/s

range=(u)square sin 2tita /g

then according to question,

range=(196)(196)( sin 2(30))/10 we know g=10

=38416 (root3)/2 /10

=38416(1.7320)/20

t=2u sin(tita)/g

=2(196)sin(30)/10

=392(1/2) /10

h max=(u) square( sin)

square (tita)/2g

=(196)square (sin)square(30)/2(10)

=38416(1/2)(1/2)/20