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A two digit number such that the product of the digit is 12 when 36 is added to that number the digits interchanges their places find the number if u you

So let the two digits be x and y so xy = 12 so 10x+y+36 = 10y+x 9y-9x= 36 y-x = 4 y = 4 + x so xy = 12 x(4+x)= 12 x² + 4x - 12 = 0 x² +6x - 2x - 12 = 0 x(x+6)-2(x+6) = 0