A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows: Rs 200 for the first day, Rs 250 for the second day, Rs 300 for the third day,etc.. the penalty for each succeeding day being Rs 50 more than for the preceeding day. how much money the contractor has to pay as penalty, if he has delayed the work by 30 days?

2

Answers

  • Brainly User
2014-11-04T21:55:15+05:30
A question about arithmetic progression. a=200 d=50 n=30 hence penalty is sum of all terms in A.P. is n/2[2a+(n-1)d] = 15(400+1450) = 27750
0
sorry..its not the answer.. the right answer is 27750 Rs..
will u please answer the right method?
Sorry I was thinking about the penalty for the 30 th day
its ok... thank u for your help... :0
2014-11-05T19:01:13+05:30
Given
 a=200
 d=50
 n=30
according to Sn=n/2[2a+(n-1)d]
30/2[2(200)+(30-1)50]
15[400+1500-50]
15[1450]
27750 Rs

1 1 1