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since we can use the power of exponent rule of

like that in the above problem the powers are as (a+b+c)^1 , so as per the rule we did it as (a +b+c)^3. we can expand it as (a+b+c)^2 * (a+b+c)

so we know the formula for (a +b +c )^2 = a^2 +b^2 +c ^2 + 2 ab + 2bc +2ca

(a^2 +b^2 +c ^2 + 2 ab + 2bc +2ca) (a+b+c)