Answers

2014-11-05T18:56:50+05:30
given that.......secФ +tanФ=k
tanФ=k-secФ
square the both sides
tan²Ф = k² + sec²Ф - 2ksecФ
tan²Ф = k² + 1 +  tan²Ф - 2ksecФ
2ksecФ = k² + 1
square
secФ = (k² + 1)/2k
sec²Ф = (k⁴ + 1 + 2k²)/4k²
cos²Ф  = 4k²/(k⁴ + 1 + 2k²)
1 - sin²Ф = 4k²/(k⁴ + 1 + 2k²)
sin²Ф = (k⁴ + 1 + 2k² - 4k²)/(k⁴ + 1 + 2k²)
sin²Ф = (k² - 1)²/(k² + 1)²
sinФ=k²-1by k²+1
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