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40 grams of sulphur reacts completely with aluminium to form aluminium sulphide. calculate: (I)the weight of aluminium required (ii) the weight of

aluminium sulphide formed in the reaction. [Al=27,S=32]



Im in primary i dont know if ill be able to reach an answer but  i will give it a try
ratio of alluminium to sulphur = 2:3
if x is amt of alluminium we need
40g *2  =  3* x
26.6 = x

now formulae is al2s3
hence its mass would be 27*2+32*3
which is 150

plz correct me if im wrong  hope its wright fingers crossed
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Ratio of aluminium to sulpher=2:3
if x is amt of aluminium we need 40g*2=3*x

now formula  is al2s3
hence its mass would be 27*2+32*3
which is 150.
0 0 0
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