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 a normal line is perpendicular to the curve at the point. f '(x) = 2x, so the slope of the normal line is -1/(2x). Assume that we're dealing with a normal line on the left side of the x-axis. In -x units (x is negative here) it will climb x/2x = 1/2 unit, so the y-intercept of the normal line is x^2 + 1/2. As x approaches 0, the y-intercept approaches 1/2, but does not cross it until x = 0, in which case the normal line is the y-axis. For all the oblique lines, there is a mirror image on the other side, which explains the three lines through (0,c).
so lines are passing through it
0 0 0
u have coppied this ans from ans.yahoo.in(in my tab....this ans is not looking clear....and it is indicating the data source from ans.yahoo.com....i have also checked it....dont copy it....
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