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The sum of the four numbers which are in arithmetic progression is 20 and product is 625. Find the numbers?

let 4 no be a-3d,a-d,a+d,a+3d
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Let us take the the four values as a-2d,a-d,a+d,a+2d
Sum of these numbers is
we can find a values by cancelling d's so a=5
now product of these values is 
taking a common we get
since a=5;
after computing we get
we can find the d value and on substituting that we can get the four values due to time i cant complete the problem but this is the concept.
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