Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Let us take the the four values as a-2d,a-d,a+d,a+2d Sum of these numbers is a-2d+a-d+a+d+a+2d=20 we can find a values by cancelling d's so a=5 now product of these values is (a-2d)*(a-d)*(a+d)*(a+2d)=625 taking a common we get a[(1-2d)*(1-d)*(1+d)*(1+2d)]=625 since a=5; after computing we get 1-5d^2+4d^4=125 4d^4-5d^2=124 we can find the d value and on substituting that we can get the four values due to time i cant complete the problem but this is the concept.