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A luminous object is placed at a distance of 30 cm from a convex lens of focal length 20 cm. On the other side of the lens at what distance from the lens

must a convex mirror of radius of curvature 10 cm be placed in order to have an upright image of the object coincident with it?
Somebody verify this
i think the mirror is supposed to be concave mirror.
jackie your ans is right can you please explain me how did you find it.
no the question is right and the answer is 50cm
please clarify what that "it" means.. if u think answer is something else. otherwise sorry.



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The word  "it" at the end of question is not clear.  what that means.  So I solve for different possibilities.  Choose what is right as per your expectation.
1st solution :
  For the convex lens:  (see 2nd  the diagram )

       u = -30 cm    v = ?  f = +20 cm
        1/v - 1/u = 1/f  
       1/v = 1/u + 1/f = -1/30 + 1/20 = 1/60 
              v = + 60 cm.
Hence the image is inverted and real at 60 cm on the other side of lens.

   The distance between object and image is  u+v = 90cm

If a convex mirror (f=10cm) is used, the rays coming from object fall on it, a virtual erect image will be formed behind the mirror.  We want this virtual image to be at the same location as the real image formed by the lens.   Then for the convex mirror, 
                  u + v = 90 cm
                  1/v + 1/(-u) = 1/f = 1/10
             10 (u - v) = u v   
              10 (90 - v - v ) = (90 - v) v
            900 - 20 v +v² - 90 v = 0
               v² -110 v +900 = 0
                     v = [110 +- √(110²-4*900) ]/2
                          = 55 +- 5 √85 = 9 cm     as v < 90 cm
            so u = 90 - 9 = 81 cm.
Distance between convex lens and convex mirror will be = 81 - 30 cm
          = 51 cm

2nd solution:
  For the convex lens:  (see the 1st  diagram)

       u = -30 cm    v = ?  f = +20 cm
        1/v - 1/u = 1/f     =>        v = + 60 cm.
Hence the image is inverted and real at 60 cm on the other side of lens.  
If a concave mirror (instead of convex mirror)  is used to make the question more meaningful.

If an object is placed at the center of curvature C of a concave mirror (at 2 f ), then the image is inverted again and then it is of the same size and is at the same location.

Hence place the convex mirror  at  2 f = 2* 10 = 20 cm from image A'B'.  So final erect image A''B'' is formed  at C center of mirror.

Distance between lens and mirror =  60+20 = 80 cm
Solution 3:

Suppose the question is supposed to be with convex mirror only:  then,

If the convex mirror is placed exactly at A'B' then, the virtual image A''B'' is formed inside the convex mirror at the same location.  However, the image A''B'' would be inverted like A'B'.    (Convex mirror always shows virtual and erect images.)
     In that case,  the distance between lens and mirror is 60 cm.

4 3 4
u could write a full answer. why write i n comments
do u have two lenses ? u r writing two lenses
It take a lot of time because I am using a tab.
And even the question though seems complicated is a simple one
You just have to calculate the first image position which should coincide with the centre of convex mirror
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