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Let the age of son = x father's age is twice the square of his son's age so age of father = 2x²

after 8 years, age of son = x+8 age of father = 2x²+8 given that father will be 4 years more than 3 times age of son so 2x²+8 = 3(x+8) + 4 ⇒2x² + 8 = 3x + 24 + 4 ⇒2x² + 8 = 3x + 28 ⇒ 2x² + 8 - 3x - 28 = 0 ⇒2x² - 3x - 20 = 0 ⇒2x² - 8x + 5x - 20 = 0 ⇒2x(x-4) + 5(x-4) = 0 ⇒(2x+5)(x-4)=0 ⇒x = 4 or x = -5/2

age can't be negative. So age of son is 4 years. age of father = 2x² = 2×4² = 32 years