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A is 3 times B, thus B is smaller than A B = A/3 So B can be 1,2 or 3 as A is less than 10.

Difference between B and D is 2 D can be either B+2 or B-2.

If B=1 or 2, D will be B+2 (as B-2 is -1 and 0, but we know that D is a positive integer). C will be D-1 or B+1. So B will be smallest.

If B=3, then D will be either 1(B-2) or 5(B+2). C is one less than D, thus C is smaller than D. C is 0 or 4. But all are positive. So C is 4. Hence B(=3) is the smallest.

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

1 <= A, B, C, D <= 9

A = 3 B => 1 <= B < 3 and 3 <= A <= 9

C = D - 1 => 1 <= C <= 8 and 2 <= D <= 9

| B - D | = 2

B is maximum 3, D is minimum 2 => B - D <= 1, if B > D.

Hence D > B and D - B = 2 => B = D -2 = C - 1

B = A/3, C - 1 and D - 2 . Hence B is the smallest.