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Sheila is now 15 years older than her younger brother sanjay.ten years from now,sheila will be twice as old as sanjay.find the present age of each of them

Answer : Let the Present age of Sanjay (in Years ) = x Therefore , Present age of Sheila = x+15 After 10 years , Shielas age = x+15+10 = x+25 sanjay's age = x+10

According to question , x+25 = 2(x+10) x+25 = 2x + 20 25 = 2x + 20 - x 25 = x+20 25 - 20 =x 5 =x or x=5 Hence Present age of Sanjay = 5 years and Present age of Shiela = x+15 = 5+15 = 20 years