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2014-11-11T04:30:23+05:30

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Draw a perpendicular PE from P to CD.  Draw a perpendicular QF from Q to BC.

Area of parallelogram ABCD = base * height
        = AB* PE = CD * PE = BC * QF 

Area of triangle PDC  = 1/2 * base * altitude = 1/2 * PE*CD

Area of triangle BQC = 1/2 * base * height = 1/2 * QF * BC

Each of the two triangle's area = 1/2 * area of parallelogram 
hence they are equal

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