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A, B , C and D are positive integers less than 10. A is 3 times of B. The difference between B and D is 2. C is1 less than D. Which is the smallest number?



*A is 3 times B, thus B is smaller than A, B = A/3 So B can be 1,2 or 3 as A is less than 10. *Difference between B and D is 2 D can be either B+2 or B-2. *If B=1 or 2, D will be B+2 (as B-2 is -1 and 0, but we know that D is a positive integer). C will be D-1 or B+1. So B will be smallest. If B=3, then D will be either 1(B-2) or 5(B+2). C is one less than D, thus C is smaller than D. C is 0 or 4. But all are positive. So C is 4.Therefore D=5. So,B(3)
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