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A mirror of length 2x is kept in front of a road as shown in fig. A point object is kept at distance x from the mirror. An observer can see the image till

distance 12x from the mirror. What is y in terms of x?




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See the diagram.

A'FC and A'GD are similar triangles.

    A'F / FC = A'G / GD

       X/X =  (X+Y) / 6X
        1 = (X+Y) / 6X
          6 X = X + Y

        Y = 5 X

0 0 0
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