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Die is tossed twice. Getting an odd number in at least a toss is termed as a success. Find the probability distribution of number of successes. Also find

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Let S = event that at least an odd number is the outcome of n tosses. = success

Let F = event that no odd number turns out = failure

n =1, then in one toss, probability of an odd number turning out = 3/6 = 1/2 P(S) = 1/2 So P(F) = 1 - 1/2 = 1/2

The tosses of die are independent. The probabilities can be multiplied.

n = 2, two tosses, P(S) = 1 - ( P(Failure) in first toss * P(Failure) in 2nd toss) = 1 - 1/2 * 1/2 = 1 - 1/4 = 3/4

probability distribution is P(n,X) : = 0 for n = 0 = 1/2 for n = 1 = 3/4 for n = 2 =