Answers

2014-11-16T19:56:41+05:30
Given that the angle of elevation of the top of the tower from a point on ground (ACB) = 30
distance between foot of the tower and the point(BC) = 30mts
height of the tower (AB) = ?
In triangle ABC,
tan C = AB/BC
 tan 30  = AB/30
 1/√3 = AB/ 30
 30/√3 = AB
AB = 30/√3×√3/√3
     = 30√3/3
AB =10√3
     = 10(1.732)
AB = 17.32 mts
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