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A (5,3), B(-1,1) and C(7,-3)are the vertices of triangle ABC. If l is the mid-point of AB and M is the mid point of AC, show that LM=1/2BC



I is the mid point of AB,

M is the midpoint of AC

Now finding distance LM
= \sqrt{ 4^{2} +  2^{2}  }  \sqrt{20}

Finding distance BC
= \sqrt{ 8^{2} +  4^{2}  }  \sqrt{80} 2 \sqrt{20}

Hence prooved that LM=1/2BC
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