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Hello aysha! the circumference of the track is given as 176m so by the formula for circumference, we get, 2r=176 so by putting the value of pi as 22/7, we can get the radius and the radius comes out to be 28m now that we have the radius of the circle , we can find it's area by using area of circle= r^2 so we get the are of the circle as 2464m^2 but what is asked is the area of the track that is formed by this big sircle and a small circle of radius 4m so we gotta reduce the area of the smaller circle to get the are of the track formed by these circles so it'll go like this area of track= 2464 - area of smaller circle again you need to use the formula for are of the circle to find the area of the smaller circle you'll get the area of the smaller circle 50.16m^2 so area of the track = 2464-50.16 = 2413.84m^2 and this may be the final answer if you have any querries , feel free to ask! i hope this helps you:)

I feel you have gone wrong incomputing the area of inner circle

check this:DATA : circumference= 176m ie 2*(22/7)*r=176 R=28 4m wide so inner circle radius=28-4 r=24m now area of circle=radius*radius(22/7) Area of R -Area of r (22/7)((28*28)-(24*24)) =(22/7)(784-576) =(22/7)*(208) =653.71428m

DATA : circumference= 176m ie 2*(22/7)*r=176 R=28 4m wide so inner circle radius=28-4 r=24m now area of circle=radius*radius(22/7) Area of R -Area of r (22/7)((28*28)-(24*24)) =(22/7)(784-576) =(22/7)*(208) =653.71428m

circumference= 176m ie 2*(22/7)*r=176 R=28 4m wide so inner circle radius=28-4 r=24m now area of circle=radius*radius(22/7) Area of R -Area of r (22/7)((28*28)-(24*24)) =(22/7)(784-576) =(22/7)*(208) =653.71428m

Basilisk is correct, solved it myself

thanks for correcting me

your welcome

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