Answers

2014-03-21T13:40:09+05:30
See here is is an example answer
solve it similarly
Solution. Since tangents to a circle is perpendicular to the radius through the point.
 OPB = Ð OQB = 90°
It is given that Ð B = 90°. Also, OP = OQ. Therefore, OPBQ is a square.
Since tangents drawn from an external point to a circle are equal in length.
DR = DS [Tangents from D]
AR = AQ [Tangents from A]
And BP = BQ [Tangents from B]
Now, DR = DS
 DR = 5 [Q DS = 5 cm (given)]
 AD – AR = 5
 23 – AR = 5
 AR = 23 – 5 = 18
 AQ = 18 [AR = AQ]
AB – BQ = 18
 29 – BQ =18 [Q AB = 29 cm (given)]
 BQ = 29 -18 = 11

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