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AD is the median of ΔABC. Therefore, it will divide ΔABC into two triangles of equal areas. ∴ Area (ΔABD) = Area (ΔACD) ⇒ ... (1) In ΔABD, E is the mid-point of AD. Therefore, BE is the median. ∴ Area (ΔBED) = Area (ΔABE) ⇒ Area (ΔBED) = Area (ΔABD) ⇒ Area (ΔBED) = Area (ΔABC) [From equation (1)] ⇒ Area (ΔBED) =
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