# ABC is an eqilateral TRIANGLE. IF P AND Q ARE TTHE MID POINTS OF AB AND AC RESPECTIVELY AND PQ IS 3CM THEN THE VALUE OF PA AND AQ IS

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by 09ayush99

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by 09ayush99

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On joining P and Q, PQ line will be parallel to line BC

By mid point theorm

1/2 of BC =PQ

BC= 2 PQ

BC=6 cm

As ABC is an equilatral Δ then AB=BC=CA

therefor P is mid point of AB ,Similarly Q is mid point of AC

PA=AQ=6/2=3cm

Now according to mid point theroem

2PQ=Bc

2*3=BC

Therefore BC=6cm

ABC is an equilateral triangle therefore AB=BC=AC

TherforeBC=AB

BC=6cm

AP=1/2BC

AP=12*6=3cm

AQ is also 3cm