# A chain of 100 links us 1m long and has a mass of 2kg .with the ends fastened together it isw set rotating at 3000rpm,in a horizontal plane.the centripetal force on each link is?

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by ritheesha

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by ritheesha

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The entire chain is along the radius of the circle in which it is rotating in a horizontal circle.

Length of each link = a = 1 m / 100 = 1 cm

mass of each link = m = 2 kg /100 = 0.02 kg

Let us consider__'n'__ th link from the center of circle. It is revolving in a circle of radius R = length of (n-1) links and 1/2 of length of nth link.

= (n - 1) 1 cm + 1/2 cm = (n - 1/2) /100 metes

average centripetal force on the nth link = m R ω² ,

where m = mass of link, R = distance of nth link from center, ω = angular velocity

= 0.02 * (n - 1/2) /100 * (2π 3000/60)² newtons

= 2π² (n - 1/2) Newtons

So average centripetal force on the center of mass of first link is : π² Newtons

on the 2nd link is 3 π². It increases by 2π² for each link.

Length of each link = a = 1 m / 100 = 1 cm

mass of each link = m = 2 kg /100 = 0.02 kg

Let us consider

= (n - 1) 1 cm + 1/2 cm = (n - 1/2) /100 metes

average centripetal force on the nth link = m R ω² ,

where m = mass of link, R = distance of nth link from center, ω = angular velocity

= 0.02 * (n - 1/2) /100 * (2π 3000/60)² newtons

= 2π² (n - 1/2) Newtons

So average centripetal force on the center of mass of first link is : π² Newtons

on the 2nd link is 3 π². It increases by 2π² for each link.