Free help with homework

Why join Brainly?

  • ask questions about your assignment
  • get answers with explanations
  • find similar questions

The speeds of two trains A and B are in the ratio of 5:6. A takes 36 minutes more than B to reach a destination. What is the time taken by A to reach the

destination to cover the same distance?
something is missing


Let the distance be 'l'. Now the velocities of A, B are 5v, 6v. Time taken to cover distance l is t(A)=l/(5v) and t(B)=l/(6v). Given that A takes 36 minutes more than B i.e. tA-tB=36. Which is l/v[1/5-1/6]=36, l/(5*6*v)=36. Hence l/(5v)=36(6). Therefore, time taken by A is 216 minutes.
0 0 0
the conparision method is good
Thank u soooo much
Let the common factor be x
Speed of A= 5x & Speed of B= 6x
Let the distance be= d
 \frac{d}{5x} = \frac{d}{6x} +36
⇒ d=1080x
Time taken by A to travel distance d=  \frac{d}{5x}
1 5 1
Hey i marked as best r u happy now
The Brain
  • The Brain
  • Helper
Not sure about the answer?
Learn more with Brainly!
Having trouble with your homework?
Get free help!
  • 80% of questions are answered in under 10 minutes
  • Answers come with explanations, so that you can learn
  • Answer quality is ensured by our experts