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A hollow iron pipe, which is 14cm long and has its external diameter 10cm. If the thickness of the pipe is 2cm and iron weighs 10g/ cm³, find the weight of

the pipe?


External radius(R)= 10-2= 5cm
Internal radius(r)= (5-2)= 3cm

Volume of the pipe= π(R²-r²)×l
                           = \frac{22}{7}×16×14

Therefore weight of the pipe= volume×density
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its on top of my answer
It's not there, tell me any anotherway
Hello there! There seems to be a mistake in your answer.
no thers not
Ok tell me how to answer the questions posted here
R=5, r=3, l=14. Volume, V=Π(R²-r²)l=Π(16)(14)=Π(224)=22(32)=704. Mass, m=10(704)=7040gms. Mass of rod is 7.04 kgs
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