Free help with homework

Why join Brainly?

  • ask questions about your assignment
  • get answers with explanations
  • find similar questions

A,B and C are three unequal faces of a rectangular tank. the tank contains a certain amount of water. when the tank is based on the face A,the height of

the water is half the height of the tank.the dimensions of the side B are 3ft x 4ft and the dimensions of the side C are 4ft x 5ft.what is the measure of the height of the water in the tank in feet?
a)2 b)3 c)4 d)5



This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Dimensions of face B = 3' * 4'
Dimensions of face C = 4' * 5'

The common side /edge between the two faces = 4'
Hence volume of the tank is = 3' * 4 ' * 5' = 60 cubic feet

Dimensions of face A of the tank = 3' * 5' = 15 sq ft

Height of full tank with face A as the base = 60/15 = 4 feet

Water level = 4'/2= 2 feet

1 5 1
click on thank you link and select best answer
Given :-
Dimensions of face B = 3ft x 4ft 
Dimensions of face C = 4ft x 5ftft

Common side between the two faces = 4ft 

So volume of the tank is = 3ft × 4ft × 5ft = 60 cubic feet

Dimensions of face A of the tank = 3ft × 5ft = 15 sq ft

Height of tank with face A( as the base ) = 60/15 = 4ft

Water level = 4ft/2= 2ft.
0 0 0
The Brain
  • The Brain
  • Helper
Not sure about the answer?
Learn more with Brainly!
Having trouble with your homework?
Get free help!
  • 80% of questions are answered in under 10 minutes
  • Answers come with explanations, so that you can learn
  • Answer quality is ensured by our experts