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A short linear object of length b lies along the axis of a concave mirror of focal length f, at a distance u

from the mirror. The size of the image is approximately:



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F = focal length
u = image distance 
let v be the image distance
height of object = b



so magnification = -v/u 

let h = object height = b
    h' = object height

so h'/h = -v/u 

    h' = -vh/u

 h'=\frac{-f*u*b}{f+u}    ANSWER

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