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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

A train covered a certain distance at a uniform speed. If the train would have been 10km/h faster , it would have taken 2hrs less than the scheduled time. And ,if the train were slower by 10km/h ; it would have taken 3hrs more than the scheduled time . Find the distance covered by them

Let the speed, time, distance be s, t, d respectively related by st=d. We are given (s+10)(t-2)=d and (s-10)(t+3)=d. You have three equations and three variables showing that it is possible to solve them. You get s=50 kmph, t=12 h, d=600 km.

Let the distance be x & the speed be s Time taken for traveling x distance = hr When the speed is 10km faster time taken is = -2 ⇒x/(s+10)=x/s-2 ⇒2s²-10x+20s=0 When the speed is 10km slower time taken is =s/x+3 ⇒3s²-10x+30s=0 equating both equations 2s²-10x+20s=3s²-10x+30s ⇒ s²-50s=0 ⇒s=50 substituting value in equation x=600