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The angle of elavation of the top of the tower from a point A on the ground is 30 degree. on moving a distance of 20 meteres towards the foot of the tower

to a point B the angle of elavation increaces to 60 degree. find the height of the tower and the distance of the tower from the point A

In rt angle ΔAQR, right angle at Q, let QR=x metre be the height of the tower and let AB= 20merte Also take BQ=y meter. tan60°=x/y=√3 x=y√3 tan30°=x/(y+20)=1/√3 sub 1 in 2, y+20=x√3 =y√3.√3 =3y 2y=20 y=10m x=10√3 =17.732m Hence the height of the tower=17.32metres The distance from the point A to the tower=30metres