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At the dog park their are several dogs with their owners. Counting heads, there are 12, counting legs, there are 38. How many dogs and owners are there?



Let the no of owners =x
Hence no of dog= 12-x
ATQ  (12-x)4 + x*2 = 38
        ⇒ 48 -4x +2x = 38
        ⇒  2x=10 or x=5
No. of owners 5 and no. of dogs=12-5=7
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