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One leg of an isosceles right angled triangle is increased by 6cm and another is increased by 4cm..the change in area is 24 cm^2..So what was the original

length of the legs??


Let x be the leg
Then area of triangle=x²/2
Now the area=(x+4)(x+6)/2
As per question (x+4)(x+6)/2-x²/2=24
                       ⇒ x²+10x+24-x²=48
                       ⇒ 10x=24
                       ⇒ x=2.4
Original length of leg is 2.4 cm
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