Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Two years ago, father was three times as old as his son and two years hence twice his age will be equal to five times that of his son. find their present

let age of father be x age of son be y given x - 2 = 3y - 2 x-3y = 0 -------- (1) 2(x+2) = 5(y+2) 2x+2 = 5y+10 2x-5y-8 = 0 --------- (2) (1)×2 ⇒ 2x - 6y = 0 (2) ⇒ 2x - 5y = 8 ------------------------------- -y = -8 y = 8 age of son is 8yrs sub y = 8 in (1) x - 3(8) = 0 x = 24 age of father is 24 yrs age of son is 8yrs.

Let age of son be x father's age two yeas back was 3(x-2) and now is 3(x-2)+2 Fathers age two years hence = 5(x+2)/2 and now is 5(x+2) -2 Hence 3x-6+2=((5x+10)/2) -2 ⇒ 6x - 8=5x+10-4 ⇒ x=14 son's age is 14 and fathers age is 38