#
Two years ago, father was three times as old as his son and two years hence twice his age will be equal to five times that of his son. find their present ages (linear equation in one variable)

2
by shriprateek

Log in to add a comment

by shriprateek

Log in to add a comment

age of son be y

given x - 2 = 3y - 2

x-3y = 0 -------- (1)

2(x+2) = 5(y+2)

2x+2 = 5y+10

2x-5y-8 = 0 --------- (2)

(1)×2 ⇒ 2x - 6y = 0

(2) ⇒ 2x - 5y = 8

-------------------------------

-y = -8

y = 8

age of son is 8yrs

sub y = 8 in (1)

x - 3(8) = 0

x = 24

age of father is 24 yrs

age of son is 8yrs.

The Brainliest Answer!