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A hydraulic machine exerts a force of 900 N on position of diameter 1.80 cm the out put force is exerted on a piston of diameter 36 cm, then output force



Applied pressure is 900N/π(0.9)²
This pressure is applied on piston dia 36 cm ⇒radius=18                                          Area of piston =π18²
Out put force is= (900N/π(0.9)²)*π18²
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