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the question is "Samita has a recurring deposit account in a bank of Rs.2000 per monthat the rate of 10% per annum. If she gets Rs,83100 at the time of maturity, find the total time for which the account was held.


M = ( R * [(1+r)n - 1 ] ) / (1-(1+r)-1/3) 
[ M - maturity amount, R = monthly installment, r=interest rate/400 , n= number of quarters]
83100 = 2000*(1+10)^n -1/ (1-(1+10)^-1/3)
find the value of n from here. 
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