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In a two digit number, the digit in the ten's place is 3 more than the digit in the one's place. 7 times the sum of the digits is 3 more than the number.

Let the two digit number be AB A = B + 3 7(A + B) = 3 + AB 7(B + B + 3) = 3 + 10A + B(where AB can be written as 10A+B) 7(2B + 3) = 3 + 10(B + 3) +B 14B + 21 = 3 + 10B + 30 + B 14B + 21 = 11B + 33 14B - 11B = 33 - 21 3B = 12 B = 4 A = B + 3 A = 4 + 3 = 7 Therefore, the two digit number is 74.