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From a circular sheet of radius 9cm, a concentric circle of radius of 5cm is removed. Find the area of the remaining sheet?(Take

 \pi as 3.14)
I need the answer soon pls.


Area of circle with radius 9cm = πr² = (9*9)π = 81πsq.cm

Let keep the π as it is.

Area of circle with radius 5cm = πr² = (5*5)π = 25πsq.cm

Area of remaining sheet = 81π - 25π = 56π  = 56*(22/7) = 8*22 = 176sq.cm

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area of circle 1.=9×9=81picmsquare   and area of 2nd=5×5=25picmsquare
remaining area=81-25=56picmsquare
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