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In a purse there are 20 rupee note ,10 rupee note and 5 rupee note .the number of 5 rupee note exceeds two time the 10 notes by one.the 20 rupee notes are

5 less than 10 rupee notes.if the total value of the money in the purse is Rs.185 ,find the number of each variety of notes

Let there be X 10Rs note no of Rs 5 note= 2X+1 no of Rs 20 note= X-5 Sum of the notes= 3X-4 value of notes= 10*X+ 5(2x+1)+20(X-5)=185 ⇒ 10X +10X+5+20X-100=185 ⇒ 40X= 280 ⇒ X=7 Rs 10 Qty 7 Rs 5 Qty 15 Rs20 Qty 2

Let the no. Of 10 rs note be x then 5 rs note= 2x + 1--- & 20 rs note = x. - 5. value Of these are 10x+10x +5 +20x - 100= 185----- next step---- =40x = 185+100-5----------
40x=280
X=280÷40=7----
No. Of 10 rs note = 7
No. Of 5 rs note=2×7+1=15-----
No. Of 20 rs note =7-5=2