Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Water flows out through a cylindrical pipe whose internal diameter is 2cm at the rate of 0.7m/sec in to a cylinderTANK,THE RADIUS OF WHOSE BASE IS 40cm.BY

HOW MUCH WILL THE LEVEL OF WATER RISE IN 30 Minutes.

Area of cross section of pipe= π1²= π cm² In 30 minutes flow of water will be = 70*π*30*60 = 2100*60π cm³ Let the level of water be 'h' Volume of water in tank will be = π40²h = 2100*60π ⇒ h = 78.75 cm Level of water would be 78.75cm

We are given inner radius of pipe, r=1cm, and rate of water flow = 70cm/s. Then volume of water leaving the pipe per second = π(1)²70 = 70πcm³. In 30 minutes the volume of water present in tank = 70π(30)(60) = 126000πcm³. Then water level, h = 126(10³)π/(π(40)²) = 1260/16 = 78.75 cm