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let Ф be the angle in pace of Thita
Let angle Ф be formed by sides a & b      
          we know        sinФ= height/a ⇒ height=a* sinФ
We have area of triangle = (height*b )/2                             
                                      = (a*sinФ*b )/2                        
                                      = ( a*b* sinФ)/2
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