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Let Ф be the angle in pace of Thita
 Let angle Ф be formed by sides a & b 
         sinФ= height/a ⇒ height=a* sinФ
We have area of triangle = \frac{1}{2} height*b
                                    = \frac{1}{2} a*sinФ*b
                                    =  \frac{1}{2} a*b* sinФ
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