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(S2O3)-2+Sb2O5->SbO+H2SO3 Balance the equation

Is the given question correct? Check once!
ya sure it is correct
the eq is nt correct ya....how cm h2 appear suddenly
That's why, I asked him to check the question. Because there's no H on L.H.S
ss ravina



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           ( S₂ O₃ )²⁻ + Sb O₅      =>    Sb O + H₂ S O₃
 Sulphur oxide and Antimony pentoxide. => Antimony monoxide + Suphurous acid

     Here on the products side, we have not any ions.  It is possible that we have Hydrogen ions on the reactants side.  Hydrogen ions are probably available through an aqueous solution.

  It is not possible to balance this equation unless we know all the reactants.

       x  ( S₂ O₃ )²⁻ + y Sb O₅ + z H⁺  + w H₂ O    =>   a * Sb O + b * H₂ S O₃
        Balance     Sulphur =>  b = 2x       
                      antimony Sb  =>      a = y
                       ionic charge    =>    2x = z
                       Hydrogen    =>    2x + 2 w = 2b = 4x  =>  w = x

       Balance oxygen now,
                       3x + 5 y + x = y + 6x        =>  4 y = 2 x    =>  x  = 2y

  Choose y = 1,

       2 ( S₂ O₃ )²⁻ +  Sb O₅ + 4 H⁺ + 2 H₂ O    ==>   Sb O  + 4 H₂  S O₃

1 5 1
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