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Of the three numbers, second is twice the first and is also thrice the third. If the average of the three numbers is 44, the largest no. is?



Let the three numbers be 3x, 6x, 2x. Their average is (3+6+2)x/3 = 44.
x =12. Then largest number, 6x = 72.
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let the second no. be= x
                    1st no. =x/2
                     3rd no= x/3
             sum of the no.s=x+x/2+x/3=44*3
                                   ⇒ 11x/6=132
                                         x=72  other two are 36,24
The largest no is 72
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