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we know for arithmetic progression Sn= [2a+(n-1)d] Progression to be AP we should have for value of n =1 we have S1 = 5 n=2 we have S2 =14 n=3 we have S3 = 27 n=4 we have S4 = 44 from above we have the numbers as 5, 9 , 13 , 17 and are in arithmetic progression we have ⇒ d = 4 a = 5 Nth term = a +(n-1)d= 5 +4n - 4= 4n + 1