Answers

2014-12-19T03:40:40+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Range of a two dimensional project in Earth's gravitational field.

Horizontal speed = u Cos A
vertical speed initial = u Sin A

vertical velocity = v= u Sin A - g t            v = 0, when t = u sin A/g
The projectile lands when t = 2 * u sin A / g.

Range = horizontal distance travelled = u CosA * 2u Sin A / g
             R = u^2  Sin 2A / g

If u =20 m/s,  and  A = 45 deg for maximum range, for a given speed u:

     R = 20 * 20 Sin(2*45) / 10                  as  g = 10 m/sec/sec

     R = 20*2 Sin90    = 40 meters

1 5 1